## CBE Questions Chapter 6 Triangles Maths Class 10

Hint:Distinguish between congruency and similarity in order to understand the concept of similar figures.

**Question.1.** Rahul claims that congruent figures are similar as well. Aman claims that similar figures are congruent as well. Who is/are correct?

(a) only Rahul

(b) only Aman

(c) Both Rahul and Aman

(d) Neither Rahul nor Aman

**Question.2.** Consider the statements below.**Statement 1:** All circles are similar.**Statement 2:** All squares are similar.**Statement 3:** All right triangles are congruent.**Statement 4:** All equilateral triangles are congruent.

Which statement is/are correct?

(a) Statement 1 and Statement 3

(b) Statement 2 and Statement 4

(c) Statement 1 and Statement 2

(d) Statement 3 and Statement 4

**Ans.1.** (a) only Rahul**Ans.2.** (c) Statement 1 and Statement 2

Hint:Distinguish between congruency and similarity in order to understand the concept of similar figures.

**Question.3.** Two similar figures are shown.

(a) x=58°, y=130°

(b) x=98°, y=76°

(c) x=82°, y=84°

(d) x=130°, \angle AOB=\angle DOC

**Question.4.** Two quadrilaterals are such that their diagonals bisect each other. What additional information is required to conclude that the quadrilaterals are similar?

(a) Opposite sides are equal

(b) Opposite angles are equal

(c) Diagonals are equal and opposite sides are equal

(d) Diagonals bisect at right angle and adjacent angles are equal

**Ans.3.** (a) x=58°, y=130°**Ans.4.** (d) Diagonals bisect at right angle and adjacent angles are equal

Hint:Compute the angles and ratio of sides of triangles in order to determine their similarity.

**Question.5.** Consider the figure below.

(a) ∆AOB~∆DOC because \frac{AO}{DO}=\frac{BO}{CO}.

(b) ∆AOB~∆DOC because \angle AOB=\angle DOC.

(c) ∆AOB~∆DOC because \frac{AO}{DO}=\frac{BO}{CO} and \angle AOB=\angle DOC.

(d) ∆AOB~∆DOC because \frac{AO}{DO}=\frac{BO}{CO} and \angle BAO=\angle CDO.

**Question.6.** Consider the figure below.**Information 1:** \angle H=70° **Information 2:** \angle J=70°

(a) Each information alone is sufficient

(b) Information (1) alone is sufficient, but Information (2) alone is not sufficient.

(c) Information (2) alone is sufficient, but Information (1) alone is not sufficient.

(d) Both information together is sufficient, but neither information alone is sufficient.

**Ans.5.** (c) ∆AOB~∆DOC because \frac{AO}{DO}=\frac{BO}{CO} and \angle AOB=\angle DOC.**Ans.6.** (a) Each information alone is sufficient

Hint:Apply basic proportionality theorem and its converse in order to determine the ratio of sides in the given triangle(s).

**Question.7.** In the figure below, BA \parallel QR.

(a) 1.8 cm

(b) 1.7 cm

(c) 1.4 cm

(d) 2.2 cm

**Question.8.** In the given figure, QR \parallel AB, RP \parallel BD, CQ=x+2, QA=x, CP=5x+4, PD=3x.

(a) 1

(b) 3

(c) 6

(d) 9

**Ans.7.** (a) 1.8 cm**Ans.8.** (a) 1

Hint:Apply various criterions of similarity in order to prove that whether given triangles are similar or not.

**Question.9.** Observe the two triangles shown below.

(a) Triangles are similar by SAS

(b) Triangles are similar by SSA

(c) Triangles are not similar as sides are not in proportion

(d) No valid conclusion about similarity of triangles can be made as angle measures are not known.

**Question.10.** Consider the triangles below.

(a) Triangles are similar as all isosceles triangles are similar.

(b) Triangles are similar as corresponding sides of the triangles are in the ratio 1:2.

(c) For triangles to be similar, the measure of \angle A=40°.

(d) For triangles to be similar, the measure of \angle A=100°.

**Ans.9.** (a) Triangles are similar by SAS**Ans.10.** (d) For triangles to be similar, the measure of \angle A=100°.

Hint:Show similarity of triangles in order to solve for given real life word problems.

**Question.11.** Nishant is 6 feet tall. At an instant, his shadow is 5 feet long. At the same instant, the shadow of a pole is 30 feet long. How tall is the tower?

(a) 24 feet

(b) 30 feet

(c) 36 feet

(d) 18 feet

**Question.12.** Rahul is 5 feet tall. He places a mirror on the ground and moves until he can see the top of a building. At the instant when Rahul is 2 feet from the mirror, the building is 48 feet from the mirror. How tall is the building?

(a) 120 feet

(b) 96 feet

(c) 240 feet

(d) 180 feet

**Ans.11.** (c) 36 feet**Ans.12.** (a) 120 feet

Hint:Compute the square of the ratio of the corresponding sides of triangles in order to find the area of similar triangles.

**Question.13.** The area of two similar triangles are a and k^{2}a. What is the ratio of the corresponding side lengths of the triangles?

(a) 1:k^{2}

(b) 1:k

(c) 1:a^{2}

(d) 1:a

**Question.14.** In the figure below, XY\parallel BC.

(a) 28

(b) 55

(c) 60

(d) 99

**Ans.13.** (b) 1:k**Ans.14.** (d) 99

Hint:Compute the area of similar triangles in order to find the relation between their sides, medians, mid points of the triangles.

**Question.15.** The ratio of the areas of two similar triangles, ABC and PQR shown below is 25:144.

(a) 5:12

(b) 25:144

(c) 12:5

(d) 5:16

**Question.16.** The ratio of the areas of two similar right triangles is 9:16. The length of one of the sides of the smaller triangle is 15 cm. How much longer is the length of the corresponding side of the larger triangle from smaller triangle?

(a) 3 cm

(b) 4 cm

(c) 5 cm

(d) 7 cm

**Ans.15.** (a) 5:12**Ans.16.** (c) 5 cm

Hint:Apply the theorem that if a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse then triangles on both sides of the perpendicular are similar to the whole triangle in order to prove Pythagoras Theorem and to each other.

**Question.17.** Observe the right triangle ABC, right angled at B as shown below.

(a) 7.5 cm

(b) 2.5 cm

(c) 6.5 cm

(d) 10.5 cm

**Question.18.** Observe the right triangle PQR, right angled at Q as shown below.

(a) \triangle PMQ \sim \triangle PQR

(b) QR^{2}=RM\cdot PR

(c) PR^{2}=PQ\cdot RQ

(d) \triangle PMQ \sim \triangle QMR

**Ans.17.** (a) 7.5 cm**Ans.18.** (c) PR^{2}=PQ\cdot RQ

Hint:Prove Pythagoras theorem and its converse in order to solve real life word problems and mathematical statements/questions.

**Question.19.** Consider the figure below.**Step 1:** \triangle APB \sim \triangle ABC **Step 2:** \frac{AP}{AB}=\frac{AB}{AC}**Step 3:** AB^{2}=AP\cdot AC

Which of these could be his next step?

(a) Prove \triangle ABC \sim \triangle PAB

(b) Prove \triangle APB \sim \triangle CPB

(c) Prove \triangle BPC \sim \triangle ABC

(d) Prove \triangle APB \sim \triangle BPC

**Question.20.** From point X, Ankit walks 112 m east to reach at point Y. From point Y, Ankit walks 15 m toward north to reach point Z. What is the straight-line distance between position when he started and his position now?

(a) 123 m

(b) 127 m

(c) 117 m

(d) 113 m

**Ans.19.** (c) Prove \triangle BPC \sim \triangle ABC **Ans.20.** (d) 113 m

Hint:Apply Pythagoras theorem and its converse in order to determine whether a given triangle is a rightangled triangle or not.

**Question.21.** Which set of lengths forms a right triangle?

(a) 5cm, 12 cm, 16 cm

(b) 7 cm, 24 cm, 25 cm

(c) 3 cm, 3 cm, 4 cm

(d) 6 cm, 7 cm, 9 cm

**Question.22.** Consider the following three claims about a triangle JKL with side lengths m, n and r.**Claim 1:** JKL is a right triangle provided n^{2}-m^{2}=r^{2}.**Claim 2:** Triangle with side lengths m+2, n+2 and r+2 is a right-angle triangle.**Claim 3:** Triangle with side lengths 2m, 2n and 2r is a right-angle triangle.

Which of these is correct?

(a) Claim 1 would be correct if n>m, n>r and Claim 2 would be correct if JKL is a right triangle.

(b) Claim 1 would be correct if r>m, r>n and Claim 2 would be correct if JKL is a right triangle.

(c) Claim 1 would be correct if n>m, n>r and Claim 3 would be correct if JKL is a right triangle.

(d) Claim 1 would be correct if r>m, r>n and Claim 3 would be correct if JKL is a right triangle.

**Ans.21.** (b) 7 cm, 24 cm, 25 cm**Ans.22.** (c) Claim 1 would be correct if n>m, n>r and Claim 3 would be correct if JKL is a right triangle.